-5x^2-4x-11x=x-1

Solution for -5x^2-4x-11x=x-1 equation:

-5x^2-4x-11x=x-1

We move all terms to the left:

-5x^2-4x-11x-(x-1)=0

We add all the numbers together, and all the variables

-5x^2-15x-(x-1)=0

We get rid of parentheses

-5x^2-15x-x+1=0

We add all the numbers together, and all the variables

-5x^2-16x+1=0

a = -5; b = -16; c = +1;
Δ = b2-4ac
Δ = -162-4·(-5)·1
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{69}}{2*-5}=\frac{16-2\sqrt{69}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{69}}{2*-5}=\frac{16+2\sqrt{69}}{-10}
$